Av(132, 213, 1234)
Generating Function
      
        \(\displaystyle -\frac{1}{x^{3}+x^{2}+x -1}\)
      
      
    Counting Sequence
      
        1, 1, 2, 4, 7, 13, 24, 44, 81, 149, 274, 504, 927, 1705, 3136, ...
      
      
    
        Implicit Equation for the Generating Function
        
      
      
      
        \(\displaystyle \left(x^{3}+x^{2}+x -1\right) F \! \left(x \right)+1 = 0\)
      
      
      
    Recurrence
      
        
        
        \(\displaystyle a \! \left(0\right) = 1\)
\(\displaystyle a \! \left(1\right) = 1\)
\(\displaystyle a \! \left(2\right) = 2\)
\(\displaystyle a \! \left(n +3\right) = a \! \left(n \right)+a \! \left(n +1\right)+a \! \left(n +2\right), \quad n \geq 3\)
      
    \(\displaystyle a \! \left(1\right) = 1\)
\(\displaystyle a \! \left(2\right) = 2\)
\(\displaystyle a \! \left(n +3\right) = a \! \left(n \right)+a \! \left(n +1\right)+a \! \left(n +2\right), \quad n \geq 3\)
Explicit Closed Form
      
        
        \(\displaystyle -\frac{\left(\left(\left(\left(-\frac{49 i}{33}+\frac{5 \sqrt{3}}{33}\right) \sqrt{11}+3 i \sqrt{3}-1\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{2}{3}}+\left(\left(-\frac{29 i}{33}-\frac{7 \sqrt{3}}{33}\right) \sqrt{11}+i \sqrt{3}+1\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}+\frac{2 i \sqrt{11}}{33}+6\right) \left(\frac{\left(\left(17 i+3 \sqrt{11}\right) \sqrt{3}-9 i \sqrt{11}-17\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{2}{3}}}{24}-\frac{i \sqrt{3}\, \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}}{6}-\frac{\left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}}{6}-\frac{1}{3}\right)^{-n}+4 \left(\frac{\left(\left(-17 i+3 \sqrt{11}\right) \sqrt{3}+9 i \sqrt{11}-17\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{2}{3}}}{24}+\frac{i \sqrt{3}\, \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}}{6}-\frac{\left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}}{6}-\frac{1}{3}\right)^{-n}+\left(\left(\left(-\frac{17 i}{33}-\frac{9 \sqrt{3}}{11}\right) \sqrt{11}+i \sqrt{3}+5\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{2}{3}}+\left(-2+\left(-\frac{4 i}{33}+\frac{6 \sqrt{3}}{11}\right) \sqrt{11}\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}-\frac{2 i \sqrt{11}}{33}+6\right) \left(\frac{\left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}}{3}-\frac{1}{3}+\frac{17 \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{2}{3}}}{12}-\frac{\left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{2}{3}} \sqrt{11}\, \sqrt{3}}{4}\right)^{-n}\right) \left(\left(\left(-\frac{27 i}{22}-\frac{9 \sqrt{3}}{22}\right) \sqrt{11}+\frac{5 i \sqrt{3}}{2}+\frac{5}{2}\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{2}{3}}-8+\left(\left(-\frac{9 i}{11}+\frac{3 \sqrt{3}}{11}\right) \sqrt{11}+i \sqrt{3}-1\right) \left(17+3 \sqrt{11}\, \sqrt{3}\right)^{\frac{1}{3}}\right)}{96}\)
      
      
    This specification was found using the strategy pack "Point Placements" and has 16 rules.
Found on January 18, 2022.Finding the specification took 1 seconds.
            
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              \(\begin{align*}
                
                F_{0}\! \left(x \right) &= F_{1}\! \left(x \right)+F_{2}\! \left(x \right)\\
                
                F_{1}\! \left(x \right) &= 1\\
                
                F_{2}\! \left(x \right) &= F_{3}\! \left(x \right)\\
                
                F_{3}\! \left(x \right) &= F_{4}\! \left(x \right) F_{5}\! \left(x \right)\\
                
                F_{4}\! \left(x \right) &= x\\
                
                F_{5}\! \left(x \right) &= F_{10}\! \left(x \right)+F_{6}\! \left(x \right)\\
                
                F_{6}\! \left(x \right) &= F_{1}\! \left(x \right)+F_{7}\! \left(x \right)\\
                
                F_{7}\! \left(x \right) &= F_{8}\! \left(x \right)\\
                
                F_{8}\! \left(x \right) &= F_{4}\! \left(x \right) F_{9}\! \left(x \right)\\
                
                F_{9}\! \left(x \right) &= F_{1}\! \left(x \right)+F_{4}\! \left(x \right)\\
                
                F_{10}\! \left(x \right) &= F_{11}\! \left(x \right)+F_{2}\! \left(x \right)\\
                
                F_{11}\! \left(x \right) &= F_{12}\! \left(x \right)\\
                
                F_{12}\! \left(x \right) &= F_{13}\! \left(x \right) F_{4}\! \left(x \right)\\
                
                F_{13}\! \left(x \right) &= F_{14}\! \left(x \right)+F_{2}\! \left(x \right)\\
                
                F_{14}\! \left(x \right) &= F_{15}\! \left(x \right)\\
                
                F_{15}\! \left(x \right) &= F_{2}\! \left(x \right) F_{4}\! \left(x \right)\\
                
                \end{align*}\)