Av(1243, 1342, 1432, 2143, 4132)
Generating Function
\(\displaystyle \frac{\left(x -2\right) \sqrt{-4 x +1}+3 x}{2 x^{3}-4 x^{2}+10 x -2}\)
Counting Sequence
1, 1, 2, 6, 19, 62, 208, 713, 2485, 8776, 31329, 112848, 409582, 1496305, 5497421, ...
Implicit Equation for the Generating Function
\(\displaystyle \left(x^{3}-2 x^{2}+5 x -1\right) F \left(x
\right)^{2}-3 x F \! \left(x \right)+1 = 0\)
Recurrence
\(\displaystyle a \! \left(0\right) = 1\)
\(\displaystyle a \! \left(1\right) = 1\)
\(\displaystyle a \! \left(2\right) = 2\)
\(\displaystyle a \! \left(3\right) = 6\)
\(\displaystyle a \! \left(4\right) = 19\)
\(\displaystyle a \! \left(n +5\right) = \frac{\left(3+2 n \right) a \! \left(n \right)}{n +5}-\frac{\left(43+17 n \right) a \! \left(n +1\right)}{2 \left(n +5\right)}+\frac{\left(51+20 n \right) a \! \left(n +2\right)}{n +5}-\frac{\left(181+53 n \right) a \! \left(n +3\right)}{2 \left(n +5\right)}+\frac{\left(81+19 n \right) a \! \left(n +4\right)}{2 n +10}, \quad n \geq 5\)
\(\displaystyle a \! \left(1\right) = 1\)
\(\displaystyle a \! \left(2\right) = 2\)
\(\displaystyle a \! \left(3\right) = 6\)
\(\displaystyle a \! \left(4\right) = 19\)
\(\displaystyle a \! \left(n +5\right) = \frac{\left(3+2 n \right) a \! \left(n \right)}{n +5}-\frac{\left(43+17 n \right) a \! \left(n +1\right)}{2 \left(n +5\right)}+\frac{\left(51+20 n \right) a \! \left(n +2\right)}{n +5}-\frac{\left(181+53 n \right) a \! \left(n +3\right)}{2 \left(n +5\right)}+\frac{\left(81+19 n \right) a \! \left(n +4\right)}{2 n +10}, \quad n \geq 5\)
This specification was found using the strategy pack "Point Placements" and has 15 rules.
Found on July 23, 2021.Finding the specification took 3 seconds.
Copy 15 equations to clipboard:
\(\begin{align*}
F_{0}\! \left(x \right) &= F_{1}\! \left(x \right)+F_{2}\! \left(x \right)\\
F_{1}\! \left(x \right) &= 1\\
F_{2}\! \left(x \right) &= F_{3}\! \left(x \right)\\
F_{3}\! \left(x \right) &= F_{10}\! \left(x \right) F_{4}\! \left(x \right)\\
F_{4}\! \left(x \right) &= F_{0}\! \left(x \right)+F_{5}\! \left(x \right)\\
F_{5}\! \left(x \right) &= F_{6}\! \left(x \right)\\
F_{6}\! \left(x \right) &= F_{0}\! \left(x \right) F_{10}\! \left(x \right) F_{7}\! \left(x \right) F_{8}\! \left(x \right)\\
F_{7}\! \left(x \right) &= F_{14}\! \left(x \right)+F_{8}\! \left(x \right)\\
F_{8}\! \left(x \right) &= F_{1}\! \left(x \right)+F_{9}\! \left(x \right)\\
F_{9}\! \left(x \right) &= F_{10}\! \left(x \right) F_{11}\! \left(x \right)\\
F_{10}\! \left(x \right) &= x\\
F_{11}\! \left(x \right) &= F_{12}\! \left(x \right)+F_{8}\! \left(x \right)\\
F_{12}\! \left(x \right) &= F_{13}\! \left(x \right)\\
F_{13}\! \left(x \right) &= F_{10}\! \left(x \right) F_{11}\! \left(x \right) F_{8}\! \left(x \right)\\
F_{14}\! \left(x \right) &= F_{9}\! \left(x \right)\\
\end{align*}\)